Question

Need help with rationalizing denominator (8√2)/(√20-√18)

Answer 1

I got \[8\sqrt{40} +24\] but the answer is \[8\sqrt{10} +24\] and idk where i went wrong need help plz

Answer 2

\[\large \frac{8\sqrt{2}}{\sqrt{20}-\sqrt{18}}\cdot
\frac{\sqrt{20}+\sqrt{18}}{\sqrt{20}+\sqrt{18}}= \]
\[\large =\frac{8\sqrt{2}(2\sqrt{5}+3\sqrt{2})}{20-18}=
\frac{16\sqrt{10}+24(2)}{2}=8\sqrt{10}+24 \]

Answer 3

how do you get \[16\sqrt{10} \]

Answer 4

oh wait nvm lol