Question

One leg of a triangle, AB, measures x+1, the other leg, AC, measures 4x, and the hypotenuse, BC, is 4x+1. Find AB. see drawing...

Answer 1

is it ?

Answer 2

\[(4x+1)^2=(4x)^2+(x+1)^2\]

Answer 3

solve for x

Answer 4

\[16x ^{2}+8x+1=16x ^{2}+x^{2}+2x+1\]

Answer 5

\[(4x+1)^2=(4x)^2+(x+1)^2 \\16x^2+8x+1 =16x^2 +x^2 +2x+1 \\x^2 -6x=0 \\x(x-6)=0 \\x=0 \\or\\ x=6\]

Answer 6

but if x=0 there is not a triangle
so x=6 is acceptable

Answer 7

Got it. Thanks so much!

Answer 8

glad 2 help