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Find the area of the region bounded by the curves. y=cos(x), y=sin(2x), x=0, x=pi/2
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start by drawing a rough sketch
u will have to split the integral : 0->pi/6 : cosx-sin(2x) pi/6->pi/2 : sin(2x)-cosx
is the answer 2
u should get 1/2 http://www.wolframalpha.com/input/?i=area+between+y%3Dcos%28x%29%2C+y%3Dsin%282x%29%2C+x%3D0%2C+x%3Dpi%2F2
can you show me the process please
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