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Can someone check this for me? Algebra 2 (radicals)
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#7 is ambiguous. It should be \(\sqrt{3x}\), but it looks like \(\sqrt{3}x.\)
isnt that the same thing??
No. The vertical bar (called a vinculum) is a grouping symbol. \(\sqrt{3x}\) means to multiply 3 and the value of x and then find the square root of the product. \(\sqrt{3}x\) means to find the square root of 3 and them multiply by the value fo x. Entirely different animals.
U can simplify 10 further. 12 root 2 + 10 root 2
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