Question

how to Transfer/Array ???

Answer 1

@Callisto help me mamen ... :D

Answer 2

int arr[rows][columns] = {{entries in first row}, {entries in second row}, ... {entries in the last row}};

Answer 3

for all 0's entries, if I remember correctly, you just need {0} for the initialization.

Answer 4

Maybe you should try the transfer part first.

Answer 5

yeah its always start at 0

Answer 6

yeah i need to transfer it..

Answer 7

but the questin is how??

Answer 8

Have you tried?

Answer 9

im now trying to answer...

Answer 10

When you do the transfer, you probably need a temp array.

Answer 11

i just need a guide to answer it...

Answer 12

Ok, tell me what you have got.

Answer 13

thats for the transfer

Answer 14

for (a=0; a<5; a++)
{
cin>>Array[a];
}
for (b=0;b<4;b++)
{
for (int c=0;c<4-b;b++)
{
if (Array[c]>Array[c+1])
{
temp=Array[c];
Array[c]=Array[c+1];
Array[c+1]=temp;
}
}
}

Answer 15

Post the whole programme here:
http://pastebin.com/
Post the link here again after you post the code here

Answer 16

ok

Answer 17

http://pastebin.com/cSvtU5MP

Answer 18

I really need to read the WHOLE programme, or else, add comments in your code. I don't even know which array is storing what values.

Answer 19

ok...
wait

Answer 20

here's my answer but im not sure..
http://pastebin.com/FJ2MNY4F

Answer 21

Sorry, you need not use a temp array...

Answer 22

ok ..
what should i do??

Answer 23

Your code looks so complicated as well.
Here's what I've got.
http://pastebin.com/nzGe8sTW

Answer 24

thank you Callisto ^_^

Answer 25

hahah

Answer 26

When you print an 2D array, you need a nested for-loop (for loop inside a for-loop)

Answer 27

uhh

Answer 28

I don't see why you need a if-else statement there as well.

Answer 29

hehehh
sorry

Answer 30

It's ok.. By the way, I just realized that I did something silly in my code. You may want to improve that code I posted.
Big thanks to @experimentX for spotting it out :)

Answer 31

hehehe
thank you @experimentX ^_^

Answer 32

yw ... both of you. it's better to write a module to print the content of arrays ... since you need to repeat it 4 times.

Answer 33

uhhh

Answer 34

@Callisto
i have some question ......
:D

Answer 35

can you help me @Callisto ??

Answer 36

?

Answer 37

what statement should i change in the Transfer if i change the 10
1
9 2
8 3
7 4
6 5

to


1 2
3 4
5 6
7 8
9 10

Answer 38

Your guess?

Answer 39

like this

Answer 40

i observe that it counts from left to right and it is increasing

Answer 41

And what have you got for this question so far?

Answer 42

what statement should i put in the program to display

1 2
3 4
5 6
7 8
9 10

Answer 43

Just to display this?

Answer 44

Use a nested for loop to do it.

Answer 45

or the statement to change the //transfer

Answer 46

to display that

Answer 47

Show me your program.

Answer 48

http://pastebin.com/nzGe8sTW

Answer 49

remember??

Answer 50

but that already correct but we need to change the //transfer to get the
1 2
3 4
5 6
7 8
9 10

Answer 51

//transfer
for(int i=0; i<5; i++){
arr2[i][0] = arr1[1][i];
}
for(int i=0; i<5; i++){
arr2[i][1] = arr1[0][i];
}

Answer 52

we need to make new one in that part..

Answer 53

So what have you tried?

Answer 54

yeah i tried but so far

Answer 55

Show me what you have got then.

Answer 56

int a;

//transfer
for(int i=0; i<5; i++){
if arr2[a][0]= arr1[1][i];

a++

Answer 57

i dont know...
hehehe

Answer 58

wait

Answer 59

the table is like this right??

00 01
10 11
20 21
30 31
40 41

Answer 60

int a;

//transfer
for(int row=0; row<2; row++){
for(int col=0; col<5; col++){
if arr2[row][0]= arr1[1][col];

Answer 61

@Callisto

Answer 62

What are you doing in this piece of code?
//transfer
for(int row=0; row<2; row++){
for(int col=0; col<5; col++){
if arr2[row][0]= arr1[1][col];

Answer 63

sorry

Answer 64

Find a paper, write the the output with that piece of code, you'll know what you were doing.

Answer 65

#include<iostream>
using namespace std;
int main()
{
int arr1[2][5]={{1,2,3,4,5}, {10,9,8,7,6}};
int arr2[5][2]={0};
int i;

//print the first array
for(int i=0; i<2; i++){
for(int j=0; j<5; j++){
cout << arr1[i][j] << " ";
}
cout << endl;
}
cout << endl;

//print the second array
for(int i=0; i<5; i++){
for(int j=0; j<2; j++){
cout << arr2[i][j] << " ";
}
cout << endl;
}

cout << "\nAfter transfer... \n" << endl;

//transfer the entry in array 1 to array 2.
for(int row=0; row<5; row++){
for( col==0)
if arr2[row][col]= arr1[row][i];
}
i++
}
return 0;

Answer 66

Have you compiled the programme?

Answer 67

for(int row=0; row<5; row++){
for( col==0)
if arr2[row][col]= arr1[row][i]; <--- what is this line doing?
i++
}

Answer 68

#include<iostream>
using namespace std;
int main() { int arr1[2][5]={{1,2,3,4,5}, {10,9,8,7,6}};
int arr2[5][2]={0};
int a;
//print the first array
for(int i=0; i<2; i++){
for(int j=0; j<5; j++){
cout << arr1[i][j] << " "; }
cout << endl; }
cout << endl;
//print the second array
for(int i=0; i<5; i++){ for(int j=0; j<2; j++){
cout << arr2[i][j] << " "; }
cout << endl; }
cout << "\nAfter transfer... \n" << endl;
//transfer the entry in array 1 to array 2.
for(int row=0; row<5; row++){
for( col==0)
if arr2[row][col]= arr2[row][a];
else arr1[1][a]=arr1[0][a];
a++
}

Answer 69

if-else is a conditional statement...
if (something)
do something here if it is true
else
do something here if it is false

Answer 70

Example:
int x = 1;
if (x == 1)
cout << "cheers" << endl; // print "cheers" if x = 1
else
cout << "NO" << endl; // print "NO" if x is not equal to 1

Answer 71

uhh

Answer 72

//transfer the entry in array 1 to array 2.
for(int row=0; row<5; row++){
for( col==0)
if arr2[row][col]= arr2[row][a];
if arr1[1][a]=arr1[0][a];
a++ }





can i make it like this??

Answer 73

Of course you can't.

Answer 74

aww

Answer 75

hhehehe

Answer 76

Have you revised before you do the programming exercises?
My advice is that you'd better revise before you carry on.

Answer 77

no

Answer 78

??

Answer 79

#include<iostream>
#include<iomanip>
using namespace std;

void main(){
int arr1[2][5]={{1,2,3,4,5},{10,9,8,7,6}};
int arr2[5][2]={0};
int x, y;

cout<<"Array 1"<<endl;

for(x=0;x<2;x++){
for(y=0;y<5;y++){
cout<<setw(2)<<arr1[x][y];}
cout<<endl;}

cout<<endl<<"Array 2:"<<endl;

for(x=0;x<5;x++){
for(y=0;y<2;y++){
cout<<setw(2)<<arr2[x][y]<<" ";}
cout<<endl;}

for(x=0;x<2;x++){
for(y=0;y<5;y++){
if(x==1){
arr2[y][0]=arr1[x][y];}
else if(x==0){
arr2[y][1]=arr1[x][y];}
}

cout<<endl<<"After Array Manipulation:"<<endl;

cout<<endl<<"Array 1"<<endl;

for(x=0;x<2;x++){
for(y=0;y<5;y++){
cout<<setw(2)<<arr1[x][y]<<" ";}
cout<<endl;}

cout<<endl<<"Array 2:"<<endl;

for(x=0;x<5;x++){
for(y=0;y<2;y++){
cout<<setw(2)<<arr2[x][y]<<" ";}
cout<<endl;}

}

Answer 80

revise??

Answer 81

Revise = study.

Answer 82

What are you trying to do in the new code?

Answer 83

yeah i need a new code on the part of Transfer..

Answer 84

Ok, you edit my code and here is what you got after your edition to my code:
Array 1
1 2 3 4 5
10 9 8 7 6

Array 2:
0 0
0 0
0 0
0 0
0 0

After Array Manipulation:

Array 1
1 2 3 4 5
10 9 8 7 6

Array 2:
0 1
0 2
0 3
0 4
0 5

Answer 85

aww
still i dont got the right answer :/

Answer 86

Do you know what the function setw(int n) does?

Answer 87

int n is infinite??
its also it defend to user until when to end

Answer 88

joke..
i dont know

Answer 89

But you added that function to your code.

Answer 90

http://pastebin.com/M3MRBEhm

Answer 91

If you don't try to write it yourself, you can never write it.

Answer 92

okok