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A row of six 1.0 N wooden blocks is being pushed across a tabletop at a constant speed by a toy tractor that exerts a force of 1.3 N on the row. What is the coefficient of kinetic friction between the wooden blocks and the tabletop? a. 0.80 c. 1.3 b. 0.22 d. 4.6
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"... at a constant speed..." This implies that the blocks are in equilibrium. Hence, the force applied by the tractor = combined frictional force Kinetic Friction = μ*N Can you solve the question now ??
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