The value of a certain car depreciates according to v(t)=18500e^-0.186t where t is the number of years after the car is purchased new. a) what will the car be worth in 18 months? b) when will the car be worth half of its original value? c) When will the car be worth less than $1000?

Question

The value of a certain car depreciates according to v(t)=18500e^-0.186t where t is the number of years after the car is purchased new.  a) what will the car be worth in 18 months? b) when will the car be worth half of its original value? c) When will the car be worth less than $1000?

anonymous · Answer

You use Logs for this question.

anonymous · Answer

yea i don't know how to.... how do you start doing this problem?

anonymous · Answer

Does e represent Euhlers number or is it just a randomly assigned letter?

anonymous · Answer

i'm pretty sure it represents euhlers.

anonymous · Answer

Ok, so then. -0.186t(1.5) * log (18500e) = car value in 18 months.

anonymous · Answer

Can't be. Won't work out to a value that'd work.

anonymous · Answer

so the answer would be... invalid..? i don't know...

perl · Answer

what a mess

anonymous · Answer

i know. i'm sorry :( i'm not that smart...

perl · Answer

|dw:1391384188206:dw|