How do I calculate the angles of a parallelogram if the acute angel 30'
do u mean that one of the given angle is 30 degrees ??
yes
okay then as in a parallelogram... oposite angles are equal therefore .. two of the angles of the parallelogram would be 30 degree... now let the unknown angle be x... and since in a parallelogram opposite angles are equal and all the angles add upto 360 therefore 2x + 60 = 360 2x = 300 x = 150 degree.. so.. the angles of the parallelogram are... 30 degree , 150 degree , 30 degree and 150 degree...
so do u want me to explain it to u in more easy way ??
yes plz
alright then..
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i have drawn a parallelogram with one angle as x... and since in a parallelogram opposite sides are equal therefore u could see the labelling so done.... is it clear till here ??
yup
so do u know what is the sum of the internal angles of a quadrilateral?
amm nope
anywayz... now put the sum of the angles of this parallelogram as 360 i.e. x + x+30 + 30 = 360 => 2x + 60 = 360 taking 60 to the Right Hand side.. then it gives us 2x = 360 - 60 i.e. 2x = 300 now x = 300/2 = 150 and hence u get ur unknown angle..:D
ok so the obtuse angles are 150
yes...:D...
oo ok thanks a lot realy c:
mention not...:D. it feels great when we explain someone something...:D
lol ya
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