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Trigonometry 13 Online
OpenStudy (anonymous):

Verify each identity: (secx-tanx)^2=(1-sinx)/(1+sinx)

OpenStudy (anonymous):

ok... one sec

OpenStudy (anonymous):

What do you think the first step is?

OpenStudy (anonymous):

to foil out the left side?

OpenStudy (anonymous):

Multiply the top and bottom by the conjugate of the bottom:

OpenStudy (anonymous):

Use Pythagorean identity

OpenStudy (anonymous):

Split it up

OpenStudy (anonymous):

for the left or right side?

OpenStudy (anonymous):

right side

OpenStudy (anonymous):

okie dokie :)

OpenStudy (anonymous):

would the conjugate be: (1+sinx)/(1-sinx)?

OpenStudy (anonymous):

well i gtg, but good luck

OpenStudy (anonymous):

ok thanks :)

OpenStudy (anonymous):

@alessandro96

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