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Assume that y varies directly with x. If y=28 when x=7, find x when y=52
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this indicates that y = 4x
"Assume that y varies directly with x" so we know that y = kx where k is some constant Then we plug in x = 7, y = 28 y = kx 28 = k*7 28/7 = k 4 = k k = 4 So the equation is y = 4x. Now plug in y = 52 and solve for x
\(\bf \begin{array}{llll} \textit{something }&\textit{varies directly to }&\textit{something else}\\ \quad \\ \textit{something }&=(\textit{some value })&\textit{something else}\\ \quad \\ y&=(n)&x \end{array}\)
y = 4(7) 28 = 28 52 = 4x divide both sides by 4
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