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Mathematics 18 Online
OpenStudy (anonymous):

solve 5c + 4 = -26.

OpenStudy (opcode):

Isolate C to one side.

OpenStudy (opcode):

@LazyDirectioner Do you know how to do that?

OpenStudy (the_fizicx99):

5c + 4 = -26. Subtract both sides 4 to isolate c 5c + 4 = -26. -4 -4 Then divide every term by 5 to isolate c. 5c = -30 /5 /5 C = ??

OpenStudy (the_fizicx99):

Typo, do the inverse operation to undo the 5 and have C alone on one side. The inverse of multiplication is division.

OpenStudy (anonymous):

@Opcode yes so th new equation would be c+4=-5.2?

OpenStudy (the_fizicx99):

No. @LazyDirectioner

OpenStudy (opcode):

Not exactly we want to get C to one side, and the numbers to the other. \[5c + 4 = -26\] When we move anything over the equal sign, we flip it (i.e. + 4 becomes -4). \[5c + 4 = -26 \implies 5c = -26 - 4\]

OpenStudy (anonymous):

@Opcode ok so....

OpenStudy (opcode):

Well what does \(-26 - 4\) equal?

OpenStudy (anonymous):

@Opcode -30

OpenStudy (opcode):

Correct! So now we have: \[5c = -30\] Do you understand how we got that so far?

OpenStudy (anonymous):

@Opcode yes so c=-6

OpenStudy (opcode):

Correct :-).

OpenStudy (opcode):

Do you know how to check your answer?

OpenStudy (anonymous):

@Opcode Thanks helped alot

OpenStudy (opcode):

No problem, anyway lets check your answer. It's really easy, and it make sure you get the correct answer.

OpenStudy (anonymous):

@Opcode ok ill do it

OpenStudy (opcode):

\[5c + 4 = -26\] We now know that \(c = -6\). To check we want to plug in our new found \(c\) value into the equation. \[5c + 4 = -26 \implies 5(-6) + 4 = -26 \implies -30 + 4 = -26 \] \[-26 = -26~\huge\color{red}{✓}\]

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