Mathematics
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OpenStudy (31356):
(4x^2 y^3 z^4)^3 (-3xy) / (-2xy^2 z^3)^2
MEDAL REWARDED!! ;)
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OpenStudy (31356):
@jim_thompson5910
@MelissaHolmes
OpenStudy (anonymous):
@jim_thompson5910 you got this... I got to go.... sorry
OpenStudy (31356):
Okay.
jimthompson5910 (jim_thompson5910):
can you simplify (4x^2 y^3 z^4)^3 for me?
jimthompson5910 (jim_thompson5910):
Or are you completely stuck here?
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OpenStudy (31356):
I am completely stuck
jimthompson5910 (jim_thompson5910):
what is 4^3?
OpenStudy (31356):
Or else I wouldn't bother to answer the question myself.
OpenStudy (31356):
64
jimthompson5910 (jim_thompson5910):
ok, there's no need to be rude now
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jimthompson5910 (jim_thompson5910):
now compute (x^2)^3
by using the rule (a^b)^c = a^(b*c)
OpenStudy (31356):
No, I think you misunderstood me, I was just saying it in a way, you know. t's polite in other countries you know.
jimthompson5910 (jim_thompson5910):
(x^2)^3 = ???
OpenStudy (31356):
Would the x stand for 1
OpenStudy (31356):
Or an understood of 1?
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jimthompson5910 (jim_thompson5910):
it has a coefficient of 1, yes
OpenStudy (31356):
Okay
OpenStudy (31356):
8
jimthompson5910 (jim_thompson5910):
(x^2)^3 = x^(2*3) = x^6 using that rule
OpenStudy (31356):
Okay
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jimthompson5910 (jim_thompson5910):
(y^3)^3 = ???
OpenStudy (31356):
3??????????
jimthompson5910 (jim_thompson5910):
use the rule posted above
jimthompson5910 (jim_thompson5910):
(a^b)^c = a^(b*c)
OpenStudy (31356):
Okay
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jimthompson5910 (jim_thompson5910):
so (y^3)^3 = ???
OpenStudy (31356):
I understand the rest now, thanks, got to go.
jimthompson5910 (jim_thompson5910):
alright