Question

1+tan^2x/tan^2x
would it be


sec^2x

csc^2x <<
12 years ago

Answer 1

is it \(\frac{1+\tan^2(x)}{\tan^2(x)}\) or is it \(1+\frac{\tan^2(x)}{\tan^2(x)}\) ?

Answer 2

the first one!

Answer 3

1 + tan^2 x = sec^2 x

sec^2 x = 1/ cos^2 x

\[\frac{ \frac{ 1 }{ \cos^{2}x } }{ \frac{ \sin^{2} x }{ \cos^{2}x } }\]\[\frac{ 1 }{ \cos^{2}x} \times \frac{ \cos^{2} }{ \sin^{2}x }\]\[\csc^{2}x\]

so u r correct !