Question

Please help i have no idea how to do this at all :'(

Find the quadratic function

y=ax^2+c with a graph that includes (0,1/3) and (-3,82/3)

A. y=3x^2 + 1/3


B. y= -3x^2 + 2/3


C. y= 3x^2 - 1/3


D. none of these

Answer 1

plug the given coordinates to the equation u got
considering ( 0 . 1/3 )
y = ax^2 + c
1/3 = a(0)^2 + c
so c = 1/3

considering (-3 , 82/3)
y = ax^2 + c
82/3 = a (-3)^2 + 1/3
82 = 27a + 1
27a = 81
a = 3

so.. the equation is
y= 3x^2 + 1/3

got it ?

Answer 2

oh wow its that simple? lol i feel so dumb thank you SO much!!!!!!

Answer 3

u r welcome...