Question

h(p(x))
h(x)= Sqrt(x+2)
p(x)= x^2-2

Answer 1

first substitute p(x) instead of x in h(x)
\[h[p(x)] = \sqrt{p(x) +2}\]

Answer 2

now.. substitute the value of p(x) in the above equation... and u will get ur answer :)
can u do that ?

Answer 3

Yes, I understand that part, but i need help solving it from there(:

Answer 4

@***[ISURU]***

Answer 5

\[\sqrt{x^{2} - 2 + 2}\]\[\sqrt{x^{2}}\]remember this one ...
\[\sqrt{a} = a^{\frac{ 1 }{ 2 } }\]
so ..this will be
\[x^{2 \times \frac{ 1 }{ 2 } } = x\]
hope this will help ya!!