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A ladder leaning against a wall makes a 60o angle with the ground. The base of the ladder is 4 m from the building. How high above the ground is the top of the ladder?
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|dw:1391494486207:dw|
they r asking u to find AB
tan (60) = AB /BC AB = BC tan(60) = 4tan(60)
exactly
so its 6.9?
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u can find the height now.. tan(60) = sqrt 3
Yes, it's 6.9. Another way to do it instead of using trig, is realizing its a special 30-60-90 triangle http://www.mathwarehouse.com/geometry/triangles/right-triangles/special-right-triangles.php
yeah!
thanks @Nikato and thanks isuru :)
u r welcome
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