A circle is described by the equation x2 + y2 + 14x + 2y + 14 = 0. What are the coordinates for the center of the circle and the length of the radius?
A) (-7, -1), 36 units
B) (7, 1), 36 units
C) (7, 1), 6 units
D) (-7, -1), 6 units

Question

A circle is described by the equation x2 + y2 + 14x + 2y + 14 = 0. What are the coordinates for the center of the circle and the length of the radius?
A) (-7, -1), 36 units
B) (7, 1), 36 units
C) (7, 1), 6 units
D) (-7, -1), 6 units

anonymous · Answer

$$
x^2 + y^2 + 14x + 2y + 14 = 0\
x^2 +14 x + 49 -49 +y^2+2y +1 -1 + 14=0\
(x+7)^2 -49 + (y+1)^2 -1 + 14 =0
$$
Can you finish it?

anonymous · Answer

$$
(x+7)^2 -49 + (y+1)^2 -1 + 14 =0\
(x+7)^2  + (y+1)^2  =49+1 -14\
(x+7)^2  + (y+1)^2  =36=6^2\
$$
What is the answer?

anonymous · Answer

Not really. Im not that great with math.

anonymous · Answer

The center is (-7,-1) and the radius is 6

anonymous · Answer

Thank you so much.

anonymous · Answer

YW