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A line has a y-intercept of 4 and a slope of 8/7. Find the equation of the line. A. y = 4x + 8/7 B. y = 4x - 7/8 C. y = 8/7x + 4 D. y = 7/8x - 4
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y-intercept of 4 means when x=0 y=4, you have a point (0,4), and the slope 8/7
use the point-slope form \[\Large{ y-y_1=m(x-x_1) }\]
\[\large{ y-(4)=\frac{8}{7}(x-0)}\]
thanks :D
no problem
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