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How do I find the secant 195 using the sum/difference identities?
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sec(195) = se(180+15) =- sec(15)=1.03
Can you use the same identity you would use for cos?
Sure. It can be easier if you express sec 195 in terms of cos. \[\sec 195^\text{o}=\frac{1}{\cos 195^\text{o}}\]
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