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Mathematics 10 Online
OpenStudy (anonymous):

Verify each identity: (cscx-secx)/(cscx+secx)=(cotx-1)/(cotx+1)

OpenStudy (***[isuru]***):

it;s simple... take a sec x from both denominator and numerator as a common factor ...

OpenStudy (anonymous):

I dont understand :(

OpenStudy (***[isuru]***):

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