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a train travels 2.5 miles on a straight track with a grade of 1 degree 10'. what is the vertical rise of the train in that distance?
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Ah, so you have the angle of \(1^\circ20`\) |dw:1391649061095:dw|
Bah, it trimmed the right... I had X over there. Then it is solve for x.
h = 2.5 Sin[(1+1/6)degrees]=(0.0509019 *5280 ft) = 268.762 ft
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