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Please help Pre-Calc 1.Write the expression as the sine, cosine, or tangent of an angle. sin 8x cos x - cos 8x sin x 2.Rewrite with only sin x and cos x. cos 2x - sin x
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looks like the "subtraction angle formula" for sine
so how would I do it? Can you please show me the step by step process of how to do it?
\[\sin(A-B)=\sin(A)\cos(B)-\cos(A)\sin(B)\] put \(A=8x,B=x\) and go from the right side to the left side
actually there is not much to do you get \[\sin(8x-x)=\sin(7x)\] and you are done
So would the second question be cos2x + sin2x +sinx?
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