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Use the zeros of the following quadratic to find the x-value of the vertex. y = x2 + 2x – 8 A. 2 B. 1 C. –1 D. –8
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What are the zeros of that quadratic?
The vertex will have an x-value which is exactly in the middle of the two zeros, because a parabola is symmetrical about the vertex.
set your equation so that it would equal to zero 0 = x^2 + 2x – 8
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