Question

implicit differentiation?

Answer 1

this is true because theta is always acute

Answer 2

oops

Answer 3

I meant A = (1/2)bc sin(theta)

Answer 4

A = 1/2 bh, sin ϴ = h/c
A = 1/2 bc sin ϴ

Answer 5

yes lol

Answer 6

so differentiating with respect to t

Answer 7

there are too many stuff to type

Answer 8

I believe it's
dA/dt = (1/2) (db/dt)c sin(theta) + (dc/dt)b sin(theta) + cos(theta)bc

Answer 9

?

Answer 10

missing some parenthesis, should be
(1/2) [ (db/dt)c sin(theta) + (dc/dt)b sin(theta) + cos(theta)bc ]

Answer 11

okay, nvm

Answer 12

mistake again, should be:
(1/2) [(db/dt)c sin(theta) + (dc/dt)b sin(theta) + cos(theta)(dtheta/dt)bc]

lol