Question

proof sum_{0}^{infty}\frac{ 2^n }{ n! }=e^2

Answer 1

\[\sum_{0}^{\infty}\frac{ 2^n }{ n! }=e^2\]

Answer 2

our teacher gave us a hint but i'm totally lost.

Answer 3

she says use the series for e^x and it should take 2 lines to prove it

Answer 4

\[e^x=\sum_{n=0}^{\infty}\frac{ x^n }{ n! }\]
\[e^2=\sum_{n=0}^{\infty}\frac{ 2^n }{ n! }\]

Answer 5

is that it? that is all you have to write to make it a proof?

Answer 6

yess since it asked to " use the series for e^x"

Answer 7

ok thank you very much

Answer 8

\(\Huge\color{green}{\text {Np ت}}\)