Question

What's the solution of
http://awesomescreenshot.com/0f22bbgf41

Answer 1

\[\sqrt{2x+4}=2+\sqrt{x}\]
squaring both side
\[\sqrt{2x+4}^{2}=(2+\sqrt{x})^{2}\]

Answer 2

\[2x+4=4+x+2*\sqrt{x}*2\]

Answer 3

\[2x-x+4-4=4*\sqrt{x}\]
\[x=4*\sqrt{x}\]
take square both side
\[x ^{2}=16*x\]

Answer 4

\[x*(x-16)=0\]

Answer 5

x=0 or x=16

Answer 6

@AngelCriner

Answer 7

Thank you... and thank you for showing me step by step