Question

solve cot^2(x)=tan^2(x)

Answer 1

\((cot(x))^2=(\dfrac{cosx}{sinx})^2\)

\((cot(x))^2=(\dfrac{cosx}{sinx})^2=(tan(x))^2=(\dfrac{sinx}{cosx})^2\)

(\(\dfrac{cosx}{sinx})^2=(\dfrac{sinx}{cosx})^2 \)

only way this works is if sinx=cosx

this occurs a \(\dfrac{\pi}4{}, \dfrac{3\pi}{4}, \dfrac{5\pi}{4}, etc\)