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Algebra
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Simplify: (16x12) /(4x2)
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\[\frac{16x^{12}}{4x^{2}}\] I'm guessing...
First do 16/4 \[\frac{4x^{12}}{x^{2}}\]
\[\frac{4x^{12}}{x^{2}} \rightarrow (4x^{12})\frac{1}{x^{2}}\] \[\frac{1}{x^{2}} = x^{-2}\] \[4x^{12}x^{-2}\] What next?
|dw:1391712125626:dw| Remember the exponent rules, when your dividing you subtract them. |dw:1391712301806:dw|
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