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if y' = x^3 -3x^2 +5 and y=4 when x=1 find and equation for y in terms of x. Y=x^4/ 4 -x^3 +5x + c
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Replace x with 1 and y with 4 and evaluate the constant.
I did but how do i write equation for y in terms of x
What would be the c value i am getting 11 but it should be 1/4
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