Question

Solve log2x-log(x-2)=0.

a.) 8
b.) -1
c.) no solution
d.) 2.5

Answer 1

start with
\[\log(\frac{2x}{x-2})=0\]

Answer 2

okay.

Answer 3

then rewrite in equivalent exponential form a s
\[\frac{2x}{x-2}=10^0\] or just
\[\frac{2x}{x-2}=1\] and solve for \(x\)

Answer 4

be careful here
let me know what you get

Answer 5

there is a trap set here
can you solve the equation i wrote above?

Answer 6

im trying to.

Answer 7

i cant do it on the calculator.

Answer 8

\[\frac{2x}{x-1}=1\]is not a calculator exercise
start with \[2x=x-2\] and solve for \(x\)

Answer 9

is it 2?

Answer 10

or just 2x=x

Answer 11

no it is \(-2\) which means there is no solution because you cannot take the log of -2

Answer 12

oh.
well thank you!

Answer 13

yw