Question

how to transfer/array manipulation in 2dimensional array ??

please help..

Answer 1

@Mertsj

Answer 2

@satellite73

Answer 3

please help guys

Answer 4

@Ashleyisakitty

Answer 5

@whpalmer4

Answer 6

@lalaly

Answer 7

@zepdrix

Answer 8

help guys

Answer 9

Sorry. I don't know this stuff.

Answer 10

aww its ok THANK YOU parin @Mertsj

Answer 11

@timo86m

Answer 12

help guys..

Answer 13

@wolfe8

Answer 14

sorry

Answer 15

awwwwwwwwwwwww

Answer 16

I learned this years ago for C. What do you use?

Answer 17

#include<iostream>
using namespace std;
int main(){
int arr1[2][5]={{1,2,3,4,5}, {10,9,8,7,6}};
int arr2[5][2]={0};
cout << "\nAfter transfer... \n" << endl;

//transfer the entry in array 1 to array 2.
for(int i=0; i<5; i++){
arr2[i][0] = arr1[1][i];
arr2[i][1] = arr1[0][i];
}

cout << "arr1" << endl;
//print the first array
for(int i=0; i<2; i++){
for(int j=0; j<5; j++){
cout << arr1[i][j] << " ";
}
cout << endl;
}
cout << endl;
cout << "arr2" << endl;
//print the second array
for(int i=0; i<5; i++){
for(int j=0; j<2; j++){
cout << arr2[i][j] << " ";
}
cout << endl;
}

return 0;

Answer 18

im using c++

Answer 19

im not sure in my answer

Answer 20

Yeah it's kinda different than C by a bit. You might wanna Google this. There are a lot of programming forums.

Answer 21

no..
there's no no answer in google

Answer 22

Transfer the values from array1 to array2 such that array2 will have the following values:

1 2
3 4
5 6
7 8
9 10

Answer 23

??

Answer 24

i dont know what to put in the program to display like that .. :/

Answer 25

please help...........

Answer 26

@bbkzr31 hey its you ^_^

Answer 27

lol

Answer 28

hahaah
sorry last time

Answer 29

oh np, I had to go work on some math :P

Answer 30

Your just wanting to start with one array and copy the contents of that array into another in C++?

Answer 31

no i just need to change /add the TRANSFER statement

Answer 32

to display this number
1 2
3 4
5 6
7 8
9 10


in 2Dimensional arrays

Answer 33

and i only have 1 hour to answer that ;/
whahah

Answer 34

and also after i answer the this
1 2
3 4
5 6
7 8
9 10

then after that i need to make a new Transfer statement and to diplay thiss (reversal)

10 9
8 7
6 5
4 3
2 1

Answer 35

You posted some code earlier in the discussion is that working correctly?

Answer 36

no..
i dont know if it is working correctly..
that only my wrong idea..

Answer 37

so you aren't able to compile the code?

Answer 38

and test it?

Answer 39

no i dont have a compiler right now

Answer 40

#include<iostream>
using namespace std;
int main(){
int arr1[2][5]={{1,2,3,4,5}, {10,9,8,7,6}};
int arr2[5][2]={0};
int arr3[5][2]={0};
int countOdd, countEven;
//print the first array
cout << "arr1" << endl;
for(int i=0; i<2; i++){
for(int j=0; j<5; j++){
cout << arr1[i][j] << " ";
}
cout << endl;
}
cout << endl;
cout << "arr2" << endl;
//print the second array
for(int i=0; i<5; i++){
for(int j=0; j<2; j++){
cout << arr2[i][j] << " ";
}
cout << endl;
}

cout << "\nAfter transfer... \n" << endl;

//transfer the entry in array 1 to array 2.
for(int i=0; i<5; i++){
arr2[i][0] = arr1[1][i];
arr2[i][1] = arr1[0][i];
}

cout << "arr1" << endl;
//print the first array
for(int i=0; i<2; i++){
for(int j=0; j<5; j++){
cout << arr1[i][j] << " ";
}
cout << endl;
}
cout << endl;
cout << "arr2" << endl;
//print the second array
for(int i=0; i<5; i++){
for(int j=0; j<2; j++){
cout << arr2[i][j] << " ";
}
cout << endl;
}

cout << "\nGet arr3 from arr2\n\n";
//do the transfer for arr3

for(int i=0; i<5; i++){
if(i%2 == 0){
arr3[countOdd][0] = arr2[i][1];
++countOdd;
}
else{
arr3[countEven][1] = arr2[i][1];
++countEven;
}
}
for(int i=4; i>= 0; i--){
if(i%2 == 0){
arr3[countEven][1] = arr2[i][0];
++countEven;
}
else{
arr3[countOdd][0] = arr2[i][0];
++countOdd;
}
}
for(int i=0; i<5; i++){
for(int j=0; j<2; j++){
cout << arr3[i][j] << " ";
}
cout << endl;
}
return 0;
}

Answer 41

Here is what you get when you run the code right now

Answer 42

aww
it is still wrong..

Answer 43

i need to display it by [2][5]

Answer 44

1 2
3 4
5 6
7 8
9 10

Answer 45

is that what you want the second array to display?

Answer 46

no

Answer 47

oh, you want to change the formatting of the print statement?

Answer 48

thats for the array 1

Answer 49

array 2 is like this
10 9
8 7
6 5
4 3
2 1

Answer 50

ok

Answer 51

so for array 1 were gonna need,

1 2
3 4
5 6
7 8
9 10

So we need to print the first two elements of array1, then the second 2, then the last element and the first of array2, and so on. We want it to print out differently, correct?

Answer 52

not understanding what you mean

Answer 53

your right ...

Answer 54

yes it should be in different statement..

Answer 55

@bbkzr31 still there???

Answer 56

//print the first array
for(int j=0; j<5; j++)

{
cout << arr1[0][j] << " " << arr1[1][4-j] << endl;
}

I changed your print for loop to display like this.

Answer 57

Is that correct?

And how do you want the second array to be displayed

Also is the second array being copied to the first one correctly yet?

Answer 58

array 1 is already correct..

Answer 59

after that the second array should display like this
1 2
3 4
5 6
7 8
9 10

Answer 60

So array one is already displaying correctly, but array two is not copying or being displayed correctly?

Answer 61

yeah

Answer 62

Hmm, this isn't making very much sense to me :/
You say it's due in 15 minutes?

Answer 63

awww
its ok :/

Answer 64

huuuuuuuu

Answer 65

but i can still submit even it is late

Answer 66

Well I am getting this now

Answer 67

cout << "\nAfter transfer... \n" << endl;

//transfer the entry in array 1 to array 2.

for(int i=0; i<5; i++)
{
arr2[0][i] = arr1[1][i];
arr2[1][i] = arr1[0][i];
}

Answer 68

And I changed the second print statement to..

Answer 69

cout << "arr2" << endl;

//print the second array

for(int j=0; j<5; j++)
{
cout << arr2[0][j] << " " << arr2[1][4-j] << endl;
}

Answer 70

uhh

Answer 71

#include<iostream>

using namespace std;


int main()
{

int arr1[2][5]={{1,2,3,4,5}, {10,9,8,7,6}};
int arr2[5][2]={0};



cout << "\nAfter transfer... \n" << endl;

//transfer the entry in array 1 to array 2.

for(int i=0; i<5; i++)
{
arr2[0][i] = arr1[1][i];
}

for(int i=0; i<5; i++)
{
arr2[1][i] = arr1[0][i];
}


cout << "arr1" << endl;
//print the first array

for(int j=0; j<5; j++)
{
cout << arr1[0][j] << " " << arr1[1][4-j] << endl;
}

cout << endl;


cout << "arr2" << endl;
//print the second array

for(int ii=0; ii < 5; ii++)
{
cout << arr2[0][ii] << " " << arr2[1][4-ii] << endl;
}

cout << endl;

// just makes the program pause
// So I can view what is happening
int pause;
cin >> pause;

return 0;

}

Answer 72

Is this correct?

Answer 73

no...

Answer 74

Hmm, What is wrong with it?

Answer 75

sorry..