Question

find the exact value of the remain functions please help Cos 4/5, 270 12 years ago

Answer 1

Given Cos Ө = 4/5, 270<angle<360
=> Cos^2 Ө = 4^2/5^2
=> Cos^2 Ө = 16/25
we have
=>sin^2 Ө +cos^2 Ө = 1
=>sin^2 Ө =1-cos^2 Ө
=>sin^2 Ө=1-16/25
=>sin^2 Ө = 9/25
=>sin Ө =3/5
=>tan Ө =sin Ө /cos Ө
=>tan Ө =[3/5]/[4/5]
=>tan Ө =3/4

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