Question

12x^2 - 4x -5 Factorize this completely plz. or any shortcut of breaking so, tell me.

Answer 1

\[x=(-b \pm \sqrt{b^2 -4ac})/2a\]
use this formula!

Answer 2

12x^2-10x+6x-5=0
2x(6x-5)+1*(6x-5)=0
(2x+1)(6x-5)=0
x=-1/2
or x=5/6

Answer 3

where a is 12, b is -4, & c is -5. in the end u'll get to values for x, use them to get the final factors ie : if the two roots are r & t then : (x+r)*(x+t)

Answer 4

behold