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Mathematics 13 Online
OpenStudy (ny,ny):

Given: AB parallel to DC, AB congruent to BC Prove: a. AD congruent to CB b. AD parallel to BC

OpenStudy (ny,ny):

|dw:1391758967757:dw|

OpenStudy (ikram002p):

|dw:1391762534125:dw| <1=<4 alternate angels <2=<3 alternate angels <2=<4 Isosceles triangle thus <1=<2=<3=<4 then <C=<A

OpenStudy (ikram002p):

<1=<4 alternate angels <2=<3 alternate angels AC common so by ASA triangle ADC congruent triangle ABC thus AD=BC

OpenStudy (ikram002p):

<D=<B

OpenStudy (ikram002p):

|dw:1391763044234:dw|

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