Question

A number cube with faces numbered 1 through 6 is rolled and a coin is tossed.

What is the probability that the number cube will show a number greater than 4 and the coin will land with tails up?

Answer 1

2/6 1/2

Answer 2

The probability of a number greater than 4 (i.e. 5 or 6) is \[\frac{2}{6}\] and the probability of a tails is \[\frac{1}{2}\] so the probability of greater than 4 and tails is: \[\frac{2}{6}*\frac{1}{2}=\frac{2}{12}=\frac{1}{6}\]

or about 16.66%

Answer 3

thanks

Answer 4

You can check this by listing every possibility and then counting the ones that meet the conditions:

1H
2H
3H
4H
5H
6H
1T
2T
3T
4T
5T
6T

That's 12 possibilities. The ones that meet our conditions are:

5T
6T

or 2 of them so:

\[\frac{2}{12}=\frac{1}{6}\]

Same as before.

Answer 5

ok thanks. i think i have one more question

Answer 6

Ok