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Divide. (2y/7x^2)/(y^3/14x^5y)
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\[\frac{4x^7}{y}\]
4/x^3x^3
I got 4x^3/y ?
i was right hahaha
hahahha
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You didn't put what I just put though?
@gabriel72alv is correct
Really? Okayy, Thank you. @isag (:
\[\frac{ 2y14x ^{5}y }{ 7x ^{2}y ^{3} } = 4y ^{2}x ^{5} / x ^{2}y ^{3} = 4x ^{3}/y\]
no! wth ? the question wasnt that
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