Heart failures are due to either natural occurrences (87%) or outside factors (13%). Outside factors are related to induced substances (73%) or foreign objects (27%). Natural occurrences are caused by arterial blockage (56%), disease (27%), or infection (17%).
a) Determine the probability that a failure is due to induced substance.
b) Determine probability that failure is due to disease or infection.

Question

Heart failures are due to either natural occurrences (87%) or outside factors (13%). Outside factors are related to induced substances (73%) or foreign objects (27%). Natural occurrences are caused by arterial blockage (56%), disease (27%), or infection (17%).
	a)	Determine the probability that a failure is due to induced substance.
b)	Determine probability that failure is due to disease or infection.

anonymous · Answer

you, 
a)Lets denote probability due induce p(I)=0.73x0.13
b) Probability due to diseas or infection = P(d)Up(i)=P(d)+p(i)=(0.17+0.27)x0.87