Question

Find length IG to the nearest hundredth of a foot. (Enter only the number.)


Attaching file

Answer 1

We know that \[sin=\frac{opp}{hyp}\] So:
\[\sin46^{o} =\frac{IG}{11}\] or \[IG=11 \times sin46^{o}\] From here you can just plug in the numbers and solve.

Answer 2

Thank you!