Question

Which expression is equivalent to this one?

k · 6 + k · s

A.
6(k + s)

B.
s(6 + k)

C.
k(6 + s)

D.
k · (6 + k) · s

Answer 1

I see that k is a factor of both terms of 6k + sk. Factor k out of that. What's left?

Then re-write k · 6 + k · s in factored form (including that k, of course).