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please help!! For an acute angle x, tanxtan(x/2) cscx-1 secx-1 secx+1
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you know tan double angle formula ?
yes it is 2tan theta/1-tan^2theta!
correct so tan x = tan 2(x/2) = ....
tanx tan(x/2) = 2 tan^2 (x/2) / (1+ tan^2 (x/2)) see if you get this ?
***** tanx tan(x/2) = 2 tan^2 (x/2) / (1- tan^2 (x/2))
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if you could get that, convert everything into sin and cos
oh okay wait let me convert it!
ummmm i got a really weird answer;; but i tried solving the whole thing and i got cscx-1
is the question really tanx tan(x/2) ??
yes HAHAHAHA
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from the given choices, i think its sec x -1
oh okay! thank you~
from the simple fact that tan x tan x/2 is 0 when x =0 and only sec x - 1 becomes 0 when x = 0
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