Question

Convert 2x^2+9x-6/x^2+x-6 into partial fractions.

Answer 1

I just need step-by-step guidance, not the answer.

Answer 2

first divide

Answer 3

did long division recently ?

Answer 4

Yes

Answer 5

good.
divide so that, degree of numerator becomes less than degree of denominator

Answer 6

I got 2 + 7x + 6/ x^2 + x -6.

Answer 7

To get a proper fraction?

Answer 8

2 + \(\dfrac{7x + 6}{ x^2 + x - 6}\)

Answer 9

that looks right,
next u need to wry about converting :
7x+ 6/ x^2 + x -6.

to partial fractions

Answer 10

(x + 3)(x - 2)

Answer 11

yes, next setup the fractions

Answer 12

Do you leave out the 2 that's what I'm confused about...

Answer 13

yup leave out the 2

Answer 14

can u wish anything simpler than 2 to integrate ? :)
leave 2 as it is, and convert the remaining fraction to partial fractions...

Answer 15

Okay, what i got \( 2+ \dfrac{4}{x-2} + \dfrac{3}{x+3}\).

Answer 16

Is that correct?

Answer 17

how did u get that ?

Answer 18

Is it wrong?

Answer 19

it is correct,
im asking how did u arrive at that...

Answer 20

\( 7x + 6=\dfrac{A}{x-2} + \dfrac{B}{x + 3}\)

Answer 21

wat happened to denominator on left side ?

Answer 22

What denominator?

Answer 23

\(\large \frac{7x + 6}{\color{red}{(x+2)(x+3)}}=\dfrac{A}{x-2} + \dfrac{B}{x + 3}\)

Answer 24

^^that denominator

Answer 25

I didn't write it.

Answer 26

I left it by mistake.

Answer 27

ok then fine :)

Answer 28

i see ur doing it right... :)

Answer 29

I didn't get it when i posted it up but then got it after.

Answer 30

Thanks :)

Answer 31

good :P