A tank can be filled by one pipe in four hours and by a second pipe in six hours; and when it is full, the tank can be drained by a third pipe in three hours. If the tank is empty and all three pipes are open, in how many hours will the tank be filled? 8 hours 12 hours 24 hours are the the first and second pipe going at the same time ?????
12
can you awsner my question at the bottom
No. Gimmie medal
know you didnt help me in any way so no
no*
Both pipes are going st the same time.
let v be the volume of tank,then in1 hr tank is full= \[\frac{ V }{ 4 }+\frac{ V }{ 6 }-\frac{ V }{ 3 }\] Calculate V
how do i get v ?
does one pipe fill up the tank in four hour while the other pipe goes for six hours .....do they fill up the tank as an addittive
in 1 hr tank is full=\[V \frac{ 3+2-4 }{ 12 }=\frac{ V }{ 12 }\] OR Tank is full in hours=1*12=12hs
we can say one 1/12 th part is full in hrs=1 tank is full in hrs=1*12/1=12 hrs.
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