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help please
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@Data_LG2
|dw:1391886834725:dw| the answer is already ^^^^^^
lol, that's fine, no problem @Loser66
:)
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wat do i do?
do you know how to use your trigonometry?
no
|dw:1391887243244:dw| \(\LARGE sin\ \theta= \frac{opposite}{hypotenuse}\) \(\LARGE tan\ \theta= \frac{opposite}{adjacent}\) \(\LARGE cos\ \theta= \frac{adjacent}{hypotenuse}\) for a square, the angle between the diagonal and the side would be 45 degrees the hypotenuse is the AC, which is 11 and you are looking for the opposite side CD |dw:1391887615778:dw| you need to use the formula for sin or cos because the adjacent, AD, is equal to the opposite, CD.
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