Question

Algebra 2
√x = 1/9

Answer 1

What is the opposite operation of a square root?\[\sqrt{x}^2 = x\]

Answer 2

did you get it?

Answer 3

\[\sqrt{x} = \frac{ 1 }{9} \]
\[x = \frac{ 1 }{ 81}\]

Answer 4

The square root of a number \(x\) is a number \(a\) which when multiplied together with itself gives you \(x\)\[\sqrt{x} = a\]\[a*a = x\]So if \[\sqrt{x} = \frac{1}9\]\[x=\frac{1}{9}*\frac{1}{9} = \frac{1}{81}\]

Answer 5

gracias a todos☺