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what expression is equivalent to \[\frac{ 4 }{ 9 } (2n-3)\] A. \[\frac{ 8 }{ 9 } n-1 \frac{ 1 }{ 3 }\] B. 2n-3 C. \[2n-\frac{ 1 }{ 3 }\] D. \[\frac{ 8 }{ 9 } n-3\]
did you try ? what do u think it is?
a or d
so you only need 4/9 * 3 \(\dfrac{4}{\cancel 9^{3}}\times \cancel 3 = \dfrac{4}{3}\)
and \(\dfrac{4}{3} = \dfrac{3+1}{3} = 1 \dfrac{1}{3}\)
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so c?
but you were confused between a and d and 1 1/3 is there only in A).
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