Question

Solve the initial value problem:

\[(x^2-\sin^2y)dx+xsin(2y)dy = 0\]
y(1) = \[\pi/3\]

Find x.

I solved x and found to be

\[x = \frac{ 7 }{ 4 } - \frac{ \sin^2y }{ x }\]

How do I rearrange x as a function of y?

Answer 1

ur asking for solve the IVP or solve for y ?

Answer 2

its IVP so i guess it wud be difficult to separate x from y

Answer 3

i mean u also have sin hmm