Solve the initial value problem:

$$(x^2-\sin^2y)dx+xsin(2y)dy = 0$$
y(1) = $$\pi/3$$

Find x.

I solved x and found to be

$$x = \frac{ 7 }{ 4 } - \frac{ \sin^2y }{ x }$$

How do I rearrange x as a function of y?

Question

Solve the initial value problem:

$$(x^2-\sin^2y)dx+xsin(2y)dy = 0$$
y(1) = $$\pi/3$$

Find x.

I solved x and found to be

$$x = \frac{ 7 }{ 4 } - \frac{ \sin^2y }{ x }$$

How do I rearrange x as a function of y?

ikram002p · Answer

ur asking for solve the IVP or solve for y ?

ikram002p · Answer

its IVP so i guess it wud be difficult to separate x from y

ikram002p · Answer

i mean u also have sin hmm