Find the volume of the solid formed by revolving the region bounded by the graphs of y=x^2 and y=10x-x^2 about the x-axis. I don't know what I did wrong but heres my answer.

2pi(5^5/5-5(5)^4/2+25(5)^3/3)

Question

Find the volume of the solid formed by revolving the region bounded by the graphs of y=x^2 and y=10x-x^2 about the x-axis. I don't know what I did wrong but heres my answer.

2pi(5^5/5-5(5)^4/2+25(5)^3/3)

tkhunny · Answer

What were your points of intersection?
What method were you using?
What did your integral(s) look like?

anonymous · Answer

My points of intersection was 5 and 0. And the equation I took the integral from was $$\int\limits_{0}^{5} \pi(10x-2x^2)^2$$

ikram002p · Answer

u need double integral cuz its revolving the region
and also a hint solid

ikram002p · Answer

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first define the area