Question

I need some help really fast. Geometry, very important.
I NEED HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

This is the question that I can't figure out.

Answer 2

those exclamation marks tho

Answer 3

I wasn't talking to anybody in particular, just trying to draw some attention.

Answer 4

@amistre64 Can you help me?

Answer 5

@monty5658 well that was helpful

Answer 6

I know right, that x helped me a lot. NOT!

Answer 7

I have no idea how to solve this but I'll try

Answer 8

something tells me that's not the original graph....

Answer 9

if I'm not mistaken, the bisecting line is really bisecting a 90 degree angle

Answer 10

I swear that it is. I just have no idea on how to solve this.

Answer 11

hmmm

Answer 12

I just sort of feel like there is an infinite number of possibilities. The side of a triangle can be any length, and in this one we do not have enough information.

Answer 13

Technically it is bisecting both the acute angle and a 90 degree angle, but I just need to know how to solve x from that informat

Answer 14

I'm confused

Answer 15

*information, my computer is acting really slow

Answer 16

*information* yes, it's not really your machine, is the site itself

Answer 17

I'm still so confused. This is my last problem, but I don't get it at all.

Plus OpenStudy is being really slow for mew at least.

Answer 18

notice what @monty5658 is suggesting

Answer 19

*me

Answer 20

I've never been taught what tan means. I am so bad at this. Is there anyway to break it down anymore I've never seen a problem where x is so haard to find.

Answer 21

hmmm do you know the pythagorean theorem?

Answer 22

Yes.

Answer 23

A little more sense. I'm going to review over everything and see if I can understand. Thanks for your help. I'll call you if I cafigure it out. Thanks for all of your help again.

Answer 24

*can figure

Sorry I have to close and open openstudy again because it is really slow for me. I can't even see what I've typed untI hit post.

Answer 25

@monty5658, can you help me a bit more. I'm not good at solving long equations. I'm stuck at the point where at this mess:

\[blank^{2}-blank^{2}=blank^{2}-blank^{2}\]

Only did it that way to save time^

Answer 26

@nikato , do you know how to solve the long equation that monty posted. I'm really confused.

Answer 27

Use foil to simplify the equation first

Answer 28

I think that this is foil, I don't remember.
First
Outer
Inner
Last

Answer 29

I don't know how to use it though.

Answer 30

But I'm not sure that's even right because you don't know if that's really a right angle.
I think you would actually solve it using proportions

And so Foil

(10x-2)(10x-2)
10x(10x) + 10x(-2) + (-2)(10x) + (-2)(-2)

Answer 31

What Nikato said..... I'm having computer issues.
Nikato, my method only requires the heights to be the same ;)

Answer 32

I'm still confused about your method @monty5658

Answer 33

Nvm, I'm sorry but Monty, your way does not work for this problem because it is not a right triangle.
U have to solve with a proportion because all you know is an angle bisector
http://www.cut-the-knot.org/triangle/AngleBisectorTheorem.shtml

So

10x-2. 8x
------ =. ------
7x. 5x+3

Answer 34

I hate math so much. When will I ever use this is the future. In the future you need to be able to do basic math unless you are majoring in math. Nobody in their right mind that hates math as much as me would major in math, therefore I would never need this again in my life.

Answer 35

So cross multiply. And solve for x

(10x-2)(5x+3) = 7x(8x)

Answer 36

Agree with Nikato. My bad, I didn't see any angles on sheet and it appeared to be a set of right trianges.

Answer 37

Can you take it from here now?

Answer 38

50x+30x, this is all I have, I don't know if this is even right.

Answer 39

50x^2+30x, I don't know. I'm bad at this.

Answer 40

No, ,multiply everything out

50x^2 +20x -6=56x^2
-56x^2. -56x^2
---------------------------
-6x^2 +20x -6=0

Answer 41

It's a quadratic equation

Factor a -2
-2(3x^2 -10x +3)=0

Answer 42

Factor
-2(x-3)(3x-1)=0

So
Solve

x-3=0. Or 3x-1=0
2 solutions for x but only one is correct

Answer 43

I think B, but I am not sure.

Answer 44

What's B?

Answer 45

3x-1=0

Answer 46

So what did you get for x when you solved it?

Answer 47

x=3?

Answer 48

Are you sure?

3x-1=0
+1. +1
------_------
3x=1
-- --
3. 3

x=?

Answer 49

.33333333333333333333333333...

Answer 50

I guess both solution work then.

But won't it be easier with A because x=3

x-3=0
+3. +3
---------
x=3

And thanks for the testimonial

Answer 51

Welcome. Thanks for your help.

Answer 52

No problem. So you actually have two solutions for this problem, 1/3 and 3

Answer 53

To check and make sure they are right, which already did, you can plug theses values into x to make sure they are right. If any side is negative, then that value of x is not right because you can't have a negative value for the length of a triangle