Tan of a d
y=1-5x^2 at P(-5,-124)
I know
m=50 by the derivative formula
problem is not sure what this means

slope is also (y-(-124))/(x-(-5))
50=(y-(-124))/(x-(-5))
slope intercept form
y=50x+126
How did they find b?

Question

Tan of a d
 y=1-5x^2 at P(-5,-124)
I know 
m=50 by the derivative formula
problem is not sure what this means

slope is also (y-(-124))/(x-(-5))
50=(y-(-124))/(x-(-5))
slope intercept form
y=50x+126
How did they find b?

mertsj · Answer

Once you know the slope is 50 you can take you point (-5,-124) and plug into y =mx+b:

$$-124=50(-5)+b$$
$$-124+250=b$$
$$126=b$$

anonymous · Answer

can you complete the square with only two terms? I did not think so.

anonymous · Answer

thank you

mertsj · Answer

yw