Question

eqaution of line
m=-1/2 (1,-2)
can you plaese answer it guys?

Answer 1

\[y-y _{1}=m(x-x _{1})\] Given gradient, \[m=-\frac{ 1 }{ 2 }\]and\[(1,-2)\]
Thus, \[y-(-2)=(-\frac{ 1 }{ 2 } )(x-1)\]\[y+2=-\frac{ 1 }{ 2 }x +\frac{ 1 }{ 2 }\] \[y=-\frac{ 1 }{ 2 }x-\frac{ 3 }{ 2 }\]

Answer 2

thanks for helping me ^_^